As you can easily check yourself, \(C^1([a,b])\) is closed under vector space operations, and so the main thing to prove here is that it is a subset of \(C^{0,1}([a,b])\text{.}\) To prove this, fix \(x,y \in [a,b]\) with \(x \ne y\text{,}\) and try to estimate the quotient in the definition of \([f]_{C^{0,1}([a,b])}\) in terms of \(f'\) using the mean value theorem. Taking a supremum, conclude that \([f]_{C^{0,1}([a,b])} \le \n
{f'}_{C^0([a,b])}\text{.}\)